JS 依照元素出現數量排序
同樣是最近遇到的狀況，需要利用陣列內元素出現的數量進行排序，以下為範例程式：
var array = ["1", "2", "4", "5", "2", "4", "2", "3"];
var str = array.toString();
var filter = [];
var result = [];
document.write("原始陣列：" + array + "<br>");
var get = function (str, tar, arr, tmp) {
if (str.indexOf(tar) >= 0) {
tmp = str.slice(str.indexOf(tar) + 1);
arr.push(tar);
get(tmp, tar, arr, tmp);
}
return arr;
}
for (i in array) {
var elm = [];
var tmp;
var fstr = filter.join();
if (fstr.indexOf(array[i]) >= 0) {
continue;
} else {
var tmp_arr = get(str, array[i], elm, tmp);
result.push(tmp_arr.length + ':' + tmp_arr[0]);
filter.push(array[i]);
}
}
result.sort();
result.reverse();
//按照出現次數排序，不刪除重複元素
var finishArray = [];
for (index in result) {
var show = result[index].split(':');
for (i = 0; i < show[0]; i++) {
finishArray.push(show[1]);
}
}
document.write("按出現次數排序，不刪除重複元素：" + finishArray + "<br>");
//按照出現次數排序，刪除重複元素
var finishArray = [];
for (index in result) {
var show = result[index].split(':');
finishArray.push(show[1]);
}
document.write("按出現次數排序，刪除重複元素：" + finishArray + "<br>");
輸出結果：
原始陣列：1,2,4,5,2,4,2,3 按出現次數排序，不刪除重複元素：2,2,2,4,4,5,3,1 按出現次數排序，刪除重複元素：2,4,5,3,1
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